Edexcel GCSE CS Paper 2 - Forecast Exam 3

Question 1: Pizza Order Calculator

📊 10 marks⏱️ 15 mins📂 Q01FINISHED.py

A pizza restaurant calculates order totals. The base prices depend on pizza size.

Prices:

Size	Code	Price
Small	S	£6.99
Medium	M	£9.99
Large	L	£12.99

Additional rules:

Extra toppings cost £1.50 each
Orders of 3 or more pizzas get 10% off the total
Delivery adds £2.50 (Y/N input)

Requirements:

Store topping price and delivery charge as constants
Input: size code, number of extra toppings, quantity, delivery (Y/N)
Calculate total and display to 2 decimal places

Size	Toppings	Qty	Delivery	Output
M	2	1	N	£12.99
L	1	3	Y	£41.62
S	0	2	N	£13.98

📖 PLS: Data Types (p.5), Selection (p.7), Formatting (p.12)

Constants: TOPPING_PRICE = 1.50 DELIVERY_CHARGE = 2.50 Input: size = input("prompt").upper() toppings = int(input("prompt")) Selection: if size == "S": price = 6.99 elif size == "M": Discount: total = total * 0.9 (10% off) Format: "£{:.2f}".format(total)

⚠️ IN THE REAL EXAM: No hints! Find this in your PLS document.

Mark Scheme (10 marks)

Point	Description	Marks
1	Constants for topping/delivery prices	(1)
2	Input size with .upper() conversion	(1)
3	Input toppings as integer	(1)
4	Input quantity as integer	(1)
5	Selection for size (S/M/L prices)	(1)
6	Calculate pizza + toppings cost	(1)
7	Multiply by quantity	(1)
8	Apply 10% discount for qty >= 3	(1)
9	Add delivery if Y	(1)
10	Correct output formatted to 2dp	(1)

📋 Model Answer

TOPPING_PRICE = 1.50
DELIVERY_CHARGE = 2.50

size = input("Enter size (S/M/L): ").upper()
toppings = int(input("Extra toppings: "))
quantity = int(input("How many pizzas: "))
delivery = input("Delivery? (Y/N): ").upper()

# Get base price
if size == "S":
    base = 6.99
elif size == "M":
    base = 9.99
else:
    base = 12.99

# Calculate subtotal
pizzaCost = base + (toppings * TOPPING_PRICE)
total = pizzaCost * quantity

# Apply bulk discount
if quantity >= 3:
    total = total * 0.9

# Add delivery
if delivery == "Y":
    total = total + DELIVERY_CHARGE

print("Total: £{:.2f}".format(total))

📝 Q01.py

# Pizza Order Calculator
# TODO: Create constants for topping price and delivery
# TODO: Input size, toppings, quantity, delivery
# TODO: Get base price using selection
# TODO: Calculate total (base + toppings) * quantity
# TODO: Apply 10% discount if 3+ pizzas
# TODO: Add delivery charge if needed
# TODO: Display total to 2 decimal places

💻 Output

Output here...

Question 2: Debugging - Turtle Traffic Light

📊 10 marks⏱️ 15 mins📂 Q02FINISHED.py

A program draws a traffic light with three filled circles (red, amber, green from top to bottom). The program has errors.

Fix these errors:

Line 1: NameError - wrong module name
Line 6: SyntaxError - missing closing bracket
Line 9: AttributeError - method name wrong (begin_fil)
Line 11: Logic error - circle should have radius 30, not 300
Add a comment on line 14 explaining what penup() does
Complete line 20 to set fill colour to "orange" for amber light
Complete line 27 to end the fill for the green light

📖 PLS: Turtle Graphics (p.14-16)

Import: import turtle Create: t = turtle.Turtle() Circle: t.circle(radius) Fill: t.fillcolor("red") t.begin_fill() t.circle(30) t.end_fill() Pen: t.penup() - lifts pen (no drawing while moving) t.pendown() - lowers pen

⚠️ Real exam: Check PLS pages 14-16 for turtle syntax!

Mark Scheme (10 marks)

Point	Description	Marks
1	Fix: `import turtle`	(1)
2	Fix: add closing bracket `Turtle()`	(1)
3	Fix: `begin_fill()` spelling	(1)
4	Fix: radius 30 not 300	(1)
5	Comment explaining penup()	(1)
6	Set fillcolor to "orange"	(1)
7	Add end_fill() for green	(1)
8-10	Code runs, draws correctly	(3)

📋 Model Answer

import turtle

t = turtle.Turtle()
t.speed("fast")

# Red light
t.fillcolor("red")
t.begin_fill()
t.circle(30)
t.end_fill()

# penup() lifts the pen so it doesn't draw while moving
t.penup()
t.goto(0, -70)
t.pendown()

# Amber light
t.fillcolor("orange")
t.begin_fill()
t.circle(30)
t.end_fill()

t.penup()
t.goto(0, -140)
t.pendown()

# Green light
t.fillcolor("green")
t.begin_fill()
t.circle(30)
t.end_fill()

t.hideturtle()
turtle.done()

📝 Q02.py

# Traffic Light - Fix the errors
import turtl

t = turtle.Turtle(
t.speed("fast")

# Red light
t.fillcolor("red")
t.begin_fil()
t.circle(300)
t.end_fill()

t.penup()
t.goto(0, -70)
t.pendown()

# Amber light
# TODO: Set fill colour to orange
t.begin_fill()
t.circle(30)
t.end_fill()

t.penup()
t.goto(0, -140)
t.pendown()

# Green light
t.fillcolor("green")
t.begin_fill()
t.circle(30)
# TODO: End the fill

t.hideturtle()
print("Traffic light complete!")

💻 Output

Click Run to draw the traffic light!

Question 3: Temperature Converter

📊 10 marks⏱️ 20 mins📂 Q03FINISHED.py

A program converts temperatures between Celsius and Fahrenheit.

Formulas:

Celsius to Fahrenheit: F = (C × 9/5) + 32
Fahrenheit to Celsius: C = (F - 32) × 5/9

Requirements:

Input the temperature as a decimal number
Input the conversion direction (C for Celsius→Fahrenheit, F for Fahrenheit→Celsius)
Validate: Celsius cannot be below -273.15 (absolute zero)
Validate: Fahrenheit cannot be below -459.67 (absolute zero)
Display result rounded to 1 decimal place with appropriate unit

Temp	Direction	Output
100	C	212.0°F
32	F	0.0°C
-300	C	Invalid temperature
-500	F	Invalid temperature

📖 PLS: Conversion (p.5), Operators (p.6), round() (p.9)

Float input: temp = float(input("prompt")) Division: Use / for decimal division Rounding: round(value, 1) for 1 decimal place Selection: if direction == "C": if temp >= -273.15: result = (temp * 9/5) + 32 Output: print(str(result) + "°F")

⚠️ Check your boundary values carefully!

Mark Scheme (10 marks)

Point	Description	Marks
1	Input temperature as float	(1)
2	Input direction with case conversion	(1)
3	Celsius validation (>= -273.15)	(1)
4	Fahrenheit validation (>= -459.67)	(1)
5	Correct C to F formula	(1)
6	Correct F to C formula	(1)
7	Round to 1 decimal place	(1)
8	Display with correct unit (°C or °F)	(1)
9	Invalid temperature message	(1)
10	All test cases correct	(1)

📋 Model Answer

temp = float(input("Enter temperature: "))
direction = input("Convert from (C/F): ").upper()

valid = True
result = 0.0

if direction == "C":
    if temp >= -273.15:
        result = (temp * 9/5) + 32
        result = round(result, 1)
        print(str(result) + "°F")
    else:
        valid = False
elif direction == "F":
    if temp >= -459.67:
        result = (temp - 32) * 5/9
        result = round(result, 1)
        print(str(result) + "°C")
    else:
        valid = False
else:
    valid = False

if not valid:
    print("Invalid temperature")

📝 Q03.py

# Temperature Converter
# Formulas:
# C to F: F = (C * 9/5) + 32
# F to C: C = (F - 32) * 5/9

temp = input("Enter temperature: ")
# TODO: Convert to float

direction = input("Convert from (C/F): ")
# TODO: Convert to uppercase

# TODO: Validate and convert based on direction
# TODO: Check absolute zero limits
# TODO: Round to 1 decimal place
# TODO: Display result with unit

💻 Output

Output here...

Question 4: Dice Game Score Calculator (Parsons)

📊 15 marks⏱️ 20 mins📂 Q04FINISHED.py

A dice game rolls two dice. The score depends on the result:

Double 6: Score = 25 points
Any other double: Score = total × 2
Not a double: Score = total

The game plays 3 rounds and totals the score.

Round	Dice 1	Dice 2	Round Score
1	6	6	25
2	3	3	12
3	4	2	6
Total			43

Rearrange the lines. DO NOT change indentation!

📖 PLS: random.randint() (p.13), for loop (p.7), Selection (p.7)

Import: import random For loop: for round in range(3): Random: dice1 = random.randint(1, 6) Double check: if dice1 == dice2: Nested: if dice1 == 6: score = 25 else: score = (dice1 + dice2) * 2

⚠️ NEVER change indentation in Parsons problems!

Mark Scheme (15 marks)

Point	Description	Marks
1	import random at top	(1)
2	Initialise total = 0	(1)
3	for loop with range(3)	(1)
4	Roll dice1 inside loop	(1)
5	Roll dice2 inside loop	(1)
6	Check for double	(1)
7	Check for double 6	(1)
8	Score = 25 for double 6	(1)
9	Score = total × 2 for other double	(1)
10	Score = total for non-double	(1)
11	Add to total inside loop	(1)
12	Print total after loop	(1)
13-15	Program runs correctly	(3)

📋 Model Answer

import random
total = 0
for round in range(3):
    dice1 = random.randint(1, 6)
    dice2 = random.randint(1, 6)
    print("Dice:", dice1, dice2)
    if dice1 == dice2:
        if dice1 == 6:
            score = 25
        else:
            score = (dice1 + dice2) * 2
    else:
        score = dice1 + dice2
    print("Round score:", score)
    total = total + score
print("Total score:", total)

📝 Q04.py

# Parsons - Rearrange lines (keep indentation!)
    print("Round score:", score)
        else:
print("Total score:", total)
    dice2 = random.randint(1, 6)
import random
            score = (dice1 + dice2) * 2
    if dice1 == dice2:
        if dice1 == 6:
for round in range(3):
total = 0
    else:
    total = total + score
    dice1 = random.randint(1, 6)
            score = 25
        score = dice1 + dice2
    print("Dice:", dice1, dice2)

💻 Output

Output here...

Question 5: Employee Payroll Calculator

📊 15 marks⏱️ 25 mins📂 Q05FINISHED.py

A company stores employee data in a file. Each line contains: Name, Hours Worked, Hourly Rate (separated by commas).

File Q05_DATA.txt:
Jones,40,15.50
Smith,45,12.00
Brown,38,18.75
Wilson,50,14.25
Taylor,35,20.00

Requirements:

Create a function calculatePay(hours, rate) that:
- Pays normal rate for first 40 hours
- Pays 1.5× rate for overtime (hours over 40)
- Returns total pay
Read data from file and calculate pay for each employee
Write Name and Pay (to 2dp) to Q05_OUTPUT.txt
Display total payroll cost

Expected calculations:

Name	Hours	Rate	Pay
Jones	40	15.50	£620.00
Smith	45	12.00	£570.00

Smith: 40×12 + 5×(12×1.5) = 480 + 90 = £570

📖 PLS: Files (p.8), Functions (p.8), split/strip (p.11)

Function: def calculatePay(hours, rate): if hours <= 40: return hours * rate else: normal = 40 * rate overtime = (hours - 40) * rate * 1.5 return normal + overtime File: for line in file: parts = line.strip().split(",") hours = float(parts[1]) Write: file.write(name + "," + "{:.2f}".format(pay) + "\n")

⚠️ Remember: overtime is hours OVER 40, not all hours!

Mark Scheme (15 marks)

Point	Description	Marks
1	Function def with two parameters	(1)
2	Check if hours <= 40	(1)
3	Normal pay calculation	(1)
4	Overtime calculation (hours-40) × rate × 1.5	(1)
5	Return statement(s)	(1)
6	Open and read input file	(1)
7	strip() and split(",")	(1)
8	Convert hours and rate to float	(1)
9	Call function and accumulate total	(1)
10-12	Functionality (levels)	(3)
13-15	Programming practice	(3)

📋 Model Answer

def calculatePay(hours, rate):
    if hours <= 40:
        return hours * rate
    else:
        normalPay = 40 * rate
        overtimePay = (hours - 40) * rate * 1.5
        return normalPay + overtimePay

totalPayroll = 0.0

inFile = open("Q05_DATA.txt", "r")
outFile = open("Q05_OUTPUT.txt", "w")

for line in inFile:
    parts = line.strip().split(",")
    name = parts[0]
    hours = float(parts[1])
    rate = float(parts[2])
    
    pay = calculatePay(hours, rate)
    totalPayroll = totalPayroll + pay
    
    outFile.write(name + ",£{:.2f}".format(pay) + "\n")

inFile.close()
outFile.close()

print("Total payroll: £{:.2f}".format(totalPayroll))

📝 Q05.py

# Employee Payroll Calculator

def calculatePay(hours, rate):
    # TODO: Calculate pay
    # Normal rate for first 40 hours
    # 1.5x rate for overtime (over 40)
    pass

# TODO: Track total payroll
# TODO: Read file, split data
# TODO: Call function for each employee
# TODO: Write name and pay to output file
# TODO: Display total payroll

💻 Output

File ops simulated. Test in IDLE.

Question 6: Hotel Room Booking System

📊 15 marks⏱️ 25 mins📂 Q06FINISHED.py

A hotel stores room information in a 2D array. Each record contains: Room Number, Type, Price per Night, Available (True/False).

The array is sorted by Room Number.

Write a program to:

Display all available rooms with their type and price
Accept a room number from the user to book
Search for the room using linear search
If found AND available: display booking confirmation and price, mark as unavailable
If found but NOT available: display "Room already booked"
If not found: display "Room not found"

Room	Type	Price	Available
101	Single	£75	True
102	Double	£120	False
201	Double	£120	True
202	Suite	£250	True

📖 PLS: 2D arrays (p.5), len() (p.9), Boolean (p.5)

Display available: for i in range(len(rooms)): if rooms[i][3] == True: print(rooms[i][0], rooms[i][1], rooms[i][2]) Linear search: found = False i = 0 while i < len(rooms) and not found: if rooms[i][0] == searchRoom: found = True else: i = i + 1 Update array: rooms[i][3] = False # Mark as booked

⚠️ Remember to UPDATE the array when booking!

Mark Scheme (15 marks)

Point	Description	Marks
1	Loop to display available rooms	(1)
2	Check availability in display loop	(1)
3	Accept room number input	(1)
4	Linear search with found flag	(1)
5	Use len() for array length	(1)
6	Mark room as unavailable (update array)	(1)
7-9	Solution design (levels)	(3)
10-12	Functionality (levels)	(3)
13-15	Programming practice	(3)

📋 Model Answer

rooms = [
    [101, "Single", 75, True],
    [102, "Double", 120, False],
    [201, "Double", 120, True],
    [202, "Suite", 250, True],
    [301, "Single", 75, True],
]

# Display available rooms
print("Available rooms:")
print("-" * 30)
for i in range(len(rooms)):
    if rooms[i][3] == True:
        print("Room", rooms[i][0], "-", rooms[i][1], "- £" + str(rooms[i][2]))
print("-" * 30)

# Get room to book
searchRoom = int(input("Enter room number to book: "))

# Linear search
found = False
i = 0
while i < len(rooms) and not found:
    if rooms[i][0] == searchRoom:
        found = True
    else:
        i = i + 1

# Process booking
if found:
    if rooms[i][3] == True:
        print("Booking confirmed for Room", rooms[i][0])
        print("Type:", rooms[i][1])
        print("Price: £" + str(rooms[i][2]) + " per night")
        rooms[i][3] = False  # Mark as booked
    else:
        print("Room already booked")
else:
    print("Room not found")

📝 Q06.py

# Hotel Room Booking System
rooms = [
    [101, "Single", 75, True],
    [102, "Double", 120, False],
    [201, "Double", 120, True],
    [202, "Suite", 250, True],
    [301, "Single", 75, True],
]

# TODO: Display all available rooms
# TODO: Get room number to book
# TODO: Linear search for room
# TODO: If found and available: confirm and mark as booked
# TODO: If found but booked: display message
# TODO: If not found: display message

💻 Output

Output here...

Edexcel GCSE Computer Science

Paper 2: Application of Computational Thinking - FORECAST EXAM 3

🎓 PRACTICE MODE

Question 1: Pizza Order Calculator

📖 PLS: Data Types (p.5), Selection (p.7), Formatting (p.12)

Mark Scheme (10 marks)

Examiner's Comments

✗ Common Errors

💡 Tip

Question 2: Debugging - Turtle Traffic Light

📖 PLS: Turtle Graphics (p.14-16)

Mark Scheme (10 marks)

Examiner's Comments

✗ Common Errors

💡 Tip

Question 3: Temperature Converter

📖 PLS: Conversion (p.5), Operators (p.6), round() (p.9)

Mark Scheme (10 marks)

Examiner's Comments

✗ Common Errors

💡 Tip

Question 4: Dice Game Score Calculator (Parsons)

📖 PLS: random.randint() (p.13), for loop (p.7), Selection (p.7)

Mark Scheme (15 marks)

Examiner's Comments

✗ Common Errors

💡 Tip

Question 5: Employee Payroll Calculator

📖 PLS: Files (p.8), Functions (p.8), split/strip (p.11)

Mark Scheme (15 marks)

Examiner's Comments

✗ Common Errors

✓ Good Practice

Question 6: Hotel Room Booking System

📖 PLS: 2D arrays (p.5), len() (p.9), Boolean (p.5)

Mark Scheme (15 marks)

Examiner's Comments

✗ Common Errors

✓ Key Insight